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5x^2=10^11
We move all terms to the left:
5x^2-(10^11)=0
We add all the numbers together, and all the variables
5x^2-100000000000=0
a = 5; b = 0; c = -100000000000;
Δ = b2-4ac
Δ = 02-4·5·(-100000000000)
Δ = 2000000000000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{2000000000000}=\sqrt{1000000000000*2}=\sqrt{1000000000000}*\sqrt{2}=1000000\sqrt{2}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-1000000\sqrt{2}}{2*5}=\frac{0-1000000\sqrt{2}}{10} =-\frac{1000000\sqrt{2}}{10} =-100000\sqrt{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+1000000\sqrt{2}}{2*5}=\frac{0+1000000\sqrt{2}}{10} =\frac{1000000\sqrt{2}}{10} =100000\sqrt{2} $
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